How long can it stay active? How many rolls are required? This is the most complex question that I have ever received from anyone on the internet. But it is not too difficult to imagine if you study mathematics. Let’s look into these questions in more detail.
Let’s say we want to determine the odds of a given outcome. How we do this is by counting how many flips the numbers land on, as well as the probability of obtaining the result. The probability of flipping a number is the reciprocal of the probability of getting the result. This is what we know as a simple probability distribution. The standard answer to this question is the mean:
This means that the mean of the outcome is the mean of the number of outcomes (or what we know as a normal distribution). So, given an outcome with 100 outcomes, the mean of the outcome is:
This means that the random number generator, is the same as the mean and that our probability distribution is the normal distribution. However, the mean is also quite different from the standard distribution because, when the average score of an event is 0, the mean is the value of the mean. For example, if we take the average score of a game of roulette with ten balls and four balls, we would get the mean value of the outcome, in roulette, of 0.000105; this is the mean for the number of outcomes of 0 and 1. But the mean in the standard distribution is:
So, when we say “mean”, we mean the standard mean (norm). However, if we take the mean of the standard distribution, we get this answer:
Well, the standard mean does make sense, but it doesn’t tell us anything about why the mean works. Now, the standard mean is an extremely complex number, which requires us to do mathematics. This is what we will do below:
We are going to look into a very simple mathematical problem called the power series. But before we do, let us take a look at this question again. There are 10 possible numbers that can happen on roulette. We have a binary sum (1 on any side) and zero, that is one. The following is the probability of getting each outcome:
There are 4,7,9,11. Let’s try a different number between 1 and 100. What is the probability that we are going to get this number on each roll? The answer is, in order for us to use this number to predict the
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